Two cars start at the same time from one point and move along two roads at right angles to each other. Their speeds are 36 km/hr and 48 km/hr respectively. After 15 seconds, the distance between them will be
Answers
Answer:
250 m
Description for Correct answer:
Distance, covered by car in 15 seconds with the speed of 48 kmph towards the north
=48×518×15=25×8=200m
Distance, covered by car is 15 second with the speed 36 km/h towards the East.
=36×518×15=150m
After 15 seconds the distance between car is
=250 m
Answer:
Speed of car 1 = 36 km/hr. = 36 ×5/18 m/s =10m/s
Distance covered in 15 seconds = Speed x Time
= 10 m/s x 15 s = 150 m
Speed of car 2 = 48 km/hr. = 48 ×5/18 m/s =40/3m/s
Distance covered in 15 seconds = Speed x Time
= 40/3 m/s x 15 s = 200 m
Since, the 2 cars have started form a point and is moving at right angle to each other,
Hence, the distance between them = Hypotenuse of a right angled triangle.
Using Pythagoras Theorem,
Distance between them