Question

Two cars start from 2 city at the same time and meet after 6 hours. If the distance between 2 city is 540 km and speed of 1 car is 4/5 of the speed of the other, find the speed of each car.

Answer 1

Answer:

Speed of first car: 50 km/h.

Speed of second car: 40 km/h.

Step-by-step explanation:

Let the speed of a car be: x (in km).

Time Travelled by the car: 6 hours.

Distance travelling by car:

$d \: = \: s \times t$

$= 6x \: (in \: km).$

Speed of the second car: 4x/5 (in km).

Time Travelled by the second car: 6 hours.

Distance Travelled by them:

$d \: = \: s \times t$

$= 6 \: \times \frac{4x}{5}$

$= \frac{24x}{5} (im \: km).$

Total distance travelled by them:

$6x \: + \: \frac{24x}{5} km.$

But, the total distance covered by them/between the two cities are given as 540km.

Therefore, we get,

$6x \: + \: \frac{24x}{5} = 540$

$\frac{30x \: + \: 24x}{5} = 540$

$\frac{54x}{5} = 540$

{Transposing 54/5 to RHS...}

$x \: = \: 540 (\frac{5}{54})$

$x = 50$

Speed of first car: x → 50 km/h.

Speed of second car: 4x/5 → 4(50)/5 → 40 km/h.

Checking the Solution...

Speed of first car: 50 km/h.

Time Travelled: 6 hours.

Distance Covered: D = S ×T

→50 × 6

→300 km

Speed of second car: 40 km/h.

Time Travelled: 6 hours.

Distance Covered: D = S ×T

→40 × 6

→240 km

Total Distance travelled: (300 + 240)

→540 km

Given distance between the cities: 540 km.

540 = 540.

{Condition Satisfied...}

Hence, the Speed of first and second cars are 50 km/h and 40 km/r, respectively.

Hope it helped you...

Kindly Mark as Brainliest...

Answer 2

Step-by-step explanation:

Answer:

Speed of first car: 50 km/h.

Speed of second car: 40 km/h.

Step-by-step explanation:

Let the speed of a car be: x (in km).

Time Travelled by the car: 6 hours.

Distance travelling by car:

d \: = \: s \times td=s×t

= 6x \: (in \: km).=6x(inkm).

Speed of the second car: 4x/5 (in km).

Time Travelled by the second car: 6 hours.

Distance Travelled by them:

d \: = \: s \times td=s×t

= 6 \: \times \frac{4x}{5}=6×

5

4x

= \frac{24x}{5} (im \: km).=

5

24x

(imkm).

Total distance travelled by them:

6x \: + \: \frac{24x}{5} km.6x+

5

24x

km.

But, the total distance covered by them/between the two cities are given as 540km.

Therefore, we get,

6x \: + \: \frac{24x}{5} = 5406x+

5

24x

=540

\frac{30x \: + \: 24x}{5} = 540

5

30x+24x

=540

\frac{54x}{5} = 540

5

54x

=540

{Transposing 54/5 to RHS...}

x \: = \: 540 (\frac{5}{54})x=540(

54

5

)

x = 50x=50

Speed of first car: x → 50 km/h.

Speed of second car: 4x/5 → 4(50)/5 → 40 km/h.

Checking the Solution...

Speed of first car: 50 km/h.

Time Travelled: 6 hours.

Distance Covered: D = S ×T

→50 × 6

→300 km

Speed of second car: 40 km/h.

Time Travelled: 6 hours.

Distance Covered: D = S ×T

→40 × 6

→240 km

Total Distance travelled: (300 + 240)

→540 km

Given distance between the cities: 540 km.

540 = 540.

{Condition Satisfied...}

Hence, the Speed of first and second cars are 50 km/h and 40 km/r, respectively.

Hope it helped you...

Kindly Mark as Brainliest...