Question

Two cars start from the opposite points of a main road, 180km apart. The first bus runs for 20 km and takes a right turn and then runs for 10km. It then tums left and runs for another
35km and takes the direction back to reach the main road. In the meantime, due to the minor break down the other bus has run only 40km along the main road. What would be the
distance between the two buses at this point?​

Answer 1

The distance between the two cars at this point is 85 km

Given:

The distance between the two cars in the beginning = 180 km

To Find:

The distance between the two cars at this point is?

Solution:

The first car covers 20 km along the main road before taking a right run. After 10 km, it again moves for 35 km. This road is parallel to the main road. It then takes a left turn and reaches the main road. We need to calculate the distance traveled by the first cover along the main road and the parallel road only.

So, the distance covered by the first car is (20 + 35) km = 55 km.

The distance traveled by the second car is 40 km.

The total distance travelled by both the cars = 55 + 40 km = 95 km

It is given that the distance between the cars is 180 km.

So, the distance between them after traveling 95 km will be 180 - 95 = 85 km.

Hence, the distance between the two cars at this point is 85 km.

#SPJ1

Answer 2

Appropriate Question:

Two buses start from the opposite points of a main road, 180km apart. The first bus runs for 20 km and takes a right turn and then runs for 10km. It then tums left and runs for another 35km and takes the direction back to reach the main road. In the meantime, due to the minor break down the other bus has run only 40km along the main road. What would be the distance between the two buses at this point?

Answer:

$\boxed{\sf \: Distance\:between\:two\:buses = 85 \: km \: }$

Step-by-step explanation:

Given that, Two buses start from the opposite points of a main road, 180km apart.

Let assume that the XY be the distance which is 180 km apart.

Further given that, The first bus runs for 20 km and takes a right turn and then runs for 10km. It then tums left and runs for another 35km and takes the direction back to reach the main road.

That means, Distance covered by first bus to be on the main road is 20 km + 35 km = 55 km.

Thus,

$\implies\sf \: \boxed{\sf \: Distance\:covered \: by\:first\:bus = 55 \: km \: }$

Further given that, in the meantime, due to the minor break down the other bus has run only 40km along the main road.

Thus,

$\implies\sf \: \boxed{\sf \: Distance\:covered \: by\:second\:bus = 40 \: km \: }$

So,

$\sf \: Total\:distance\:covered\:by\:two\:buses = 55 + 40 = 95 \: km$

Now,

$\sf \: Distance\:between\:two\:buses = 180 - 95 = 85 \: km$

Hence,

$\implies\sf \: \boxed{\sf \: Distance\:between\:two\:buses = 85 \: km \: }$