two cars start of with velocities 4m/s and 2m/s and travel in straight line with uniform accelerations 1m/s square and 2m/s square. if they reach the final point at same time, what is the distance
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Distance traveled by each car is same in the same time.
s = u t + 1/2 a t^2
So. 4 t + 1/2 * 1 * t^2 = 2 t + 1/2 * 2* t^2
So t = 0 or t = 4 sec.
Distance = 2*4 + 1/2 * 2 *4^2
= 24 meters
s = u t + 1/2 a t^2
So. 4 t + 1/2 * 1 * t^2 = 2 t + 1/2 * 2* t^2
So t = 0 or t = 4 sec.
Distance = 2*4 + 1/2 * 2 *4^2
= 24 meters
thecoolstaryash:
thank you my man
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Refer https://brainly.in/question/16279650
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