Question

two cars start off to race with a velocity 4m/s and 2m/s travel in a straight line with a uniform acceleration of 1m/s2 and 2m/s2 respectively.if they reach the final point at the same instant , then the lenght of the path is ----

Answer 1

s = 4t + 1/2 (1) t^2
= 2t + 1/2 (2) t^2
=> t = 0 or t = 4s
Therefore
s = 4(4) + 1/2 (1)4^2
= 24m

Answer 2

Answer:

The length of the path is 24 m

Explanation:

First, let us find the time taken by each car

The velocity of the first car is  $C_{1}=4 \frac{m}{s}$

The velocity of the first car is $C_{2}=2 \frac{m}{s}$

The acceleration of the first car is $C_{A 1}=1 \frac{m}{s^{2}}$

The acceleration of the first car is $C_{A 2}=2 \frac{m}{s^{2}}$

The time formula is

For the first car is  

$v=u+a t_{1}$

$4=0+1 t_{1}$

$t_{1}=4 \sec$

For the second car is  

$v=u+a t_{2}$

$2=0+2 t_{2}$

$t_{2}=1 \sec$

Taking the majority time required that is $t_{1}=4 \sec$

The distance required is $S=u t+\frac{1}{2} a t^{2}$

$S=4.4+\frac{1}{2} .1 .4 .4=24 m$

Therefore, the distance covered by the car is 24 m.