Question

Two cars start racing from the same point at the same time. Let X and Y indicate the constant random speeds of these cars in km/hours
with a joint pdf of fx/(XY)=k x2y for 77<x<117,77<y<117 and zero otherwise. What is the probability that the car in the second place is at
least 80 kilometres away from the starting point after one hour of racing?
k=6/(7,760x1,145,080)

solve as soon as possible​

Answer 1

Answer:

Let the average speed of the slower car = V

Let the average speed of the faster car = V+8

They are travelling in opposing direction.

So, we should add those speeds (V+(V+8)) = 2V+8 and that will yield the distance of 208 miles in 2 hours.

Using the formula Distance = Speed * Time we get,

208 = (2V+8) * 2

or, 104 = 2V+8 [diving by 2 from both sides]

or, 96 = 2V [subtracting 8 from both sides]

or, 48 = V [diving by 2 from both sides]

So, the average speed of the slower car is 48 mph

And, the average speed of the faster car is (48+8)= 56 mph