Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance traveled by car B when the both the Cars meet for the first time?
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In first 66 hours, first car travels 6+5+4+3+2+16+5+4+3+2+1 km more than the second car.
In 7th7th hour, both cars travel same distance.
In next 66 hours, second car travels 1+2+3+4+5+61+2+3+4+5+6 km more than first car and both cars meet.
Therefore, total travelling time is 1313 hours. In this time, each car travels 13×12=15613×12=156 km.
In 7th7th hour, both cars travel same distance.
In next 66 hours, second car travels 1+2+3+4+5+61+2+3+4+5+6 km more than first car and both cars meet.
Therefore, total travelling time is 1313 hours. In this time, each car travels 13×12=15613×12=156 km.
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