Two cars started of the race with acceleration 3m/s² and 8m/s². Find the time after which the separation between them is 36km
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QUESTION:-
Two cars started of the race with acceleration 3m/s² and 8m/s². Find the time after which the separation between them is 36km
EXPLANATION:-
Let us label the two cars as A,B
So,
a₁=3 m/s²
a₂= 8m/s²
So using 2nd equation of motion:-
S=ut+1/2at²
S=+1/2a₁t²
and
S=+1/2a₂t²
So basically we have to find the change in distance(ΔS)
So,
ΔS=1/2a₁t²-1/1a₂t²
ΔS=(a₁-a₂)/2t²
Since
ΔS=36 km=36000 m
So putting values:-
36000=(8-3)/2t²
t=√36000/2.5
t=√14400
t=120 s
So the time is 120 s
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