Question

Two cars travel from city A to city B at a speed of 60 and 108 km/hr respectively. If one car takes 2 hours lesser time than the other car for the journey,then the distance between City A and City B?

Answer 1

suppose the distance be d km.the then let the time taken by the second car be=d/108 hrs and by the first car=d/60hrs. then we have,

d/60-d/108=2hrs=>d(1/60-1/108)=2
=>d(9-5/540)=2.
=>d(1/135)=2
=>d=270km.
hence the distance between the two cities is 270km

Answer 2

Answer:

270 km

Step-by-step explanation:

Let x be the distance between the City A and City B  

Car 1 Case:

Distance =x

Speed of Car 1 = 60 km/hr

$Time =\frac{Distance}{Speed}$

$Time =\frac{x}{60}$

Car 2 Case:

Distance =x

Speed of Car 2 = 108 km/hr

$Time =\frac{Distance}{Speed}$

$Time =\frac{x}{108}$

Now we are given that one car takes 2 hours lesser time than the other car for the journey

So, $\frac{x}{60}-\frac{x}{108}=2$

$\frac{x}{135}=2$

$x=135 \times 2$

$x=270$

Hence the distance between City A and City B is 270 km.