Question

two cars travels in a same direction along A straight highway, one at 50 kilometres per hour and the other at 60 kilometres per hour.
how far must the faster car travel before it has a 15 minutes lead on the slower car?​

Answer 1

Explanation:

2nd car has been more faster than 1st

Answer 2

Answer:

750 kelometres minute per hour

Explanation:

veocity =displacement /time .

displacement = v×t .

velocity of first car =50km /h.

time difference in two car's travelling =15minutes . displacement of first car by =50×15=750 km m/h.