Question

Two cars X and Y accelerates at the rate of 2m/s^2 and 3 m/s2 respectively from rest.The ratio of the time taken by the cars X and Y is 4:5.In that given ratio of of time interval if the distance travalled by the car x is 100km,then the distance travelled by car Y is ? please help me with the correct answer ​

Answer 1

Answer :

Acceleration of car X = 2m/s² and that for car Y is 3m/s².

Ratio of time taken by the cars X and Y = 4:5

Distance covered by car X = 100km

We have to find distance covered by car Y$.$

Since, acceleration of both cars is said to be constant throughout the motion, we can apply equation of kinematics to solve this question.

Second equation of kinematics is given by

• S = ut + 1/2(at²)

ATQ, initial velocity of cars = zero

Therefore, S ∝ at²

➝ S/S' = a/a' × t²/t'²

➝ 100/S' = 2/3 × (4/5)²

➝ 100/S' = 2/3 × 16/25

➝ S' = 7500/32

➝ S' = 234.37 m

Cheers!