Two cars x and y start from two places a and b respectively which are 840km apart at 9
a.M. Both the cars run at an average speed of 60 km/hr. When do these two cars cross each other?
Answers
car x and car y cross each other at 4 : 00 P.M
speed of both cars is same i.e., 60 km/h
as both are moving in opposite directions. so relative speed of cars = 60 + 60 = 120 km/h
seperation between car x and car y = 840km
time taken to cross each other , t = seperation between cars/relative speed of cars
= 840 km/(120 km/h)
= 7 hrs.
so, time when they cross = 9:00 A.M + (7hrs) = 4:00 P.M
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(b) Distance travelled by X upto 11 a.m. = Distance
travelled by X upto 10 a.m. = 60 × 1 = 60 km.
Distance travelled by Y upto 11 a.m. = 2 × 60 = 120
Now, at 11 a.m., distance between X and Y
= 700 – (120 + 60) = 520 km.hr.
Relative speed of X with respect to Y
= 60 – (–60) = 120 km/hr.