Two cars X and Y started moving towards each other simultaneously from two places A and B respectively, which are 60 km apart. They meet after 6 hours. After their meeting, X reduced its speed by 2 km/h and Y increased its speed by 2 km/h. They arrived at B and A respectively at the same time. Find the initial speed (in km/h) of X.
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Since, the speed of X and Y are 60 km/h each. The distance between A and B is 700 km. Distance traveled by X upto 11 am is 60 km. Since, X stops at 10 am and distance traveled by up to 11 am is 120 km.
Now, the distance between them = 700 - 180 = 520 km
Now, let they will meet at a distance of x km from X's position.
∴ Distance traveled by X = x km
and distance traveled by Y = (520 - x) km
∴ x/60 = (520 - x)/60
⇒ 2x = 520
⇒ x = 260
∴ T = 260/60 = 41/3 h
Thus, they will cross each other after, 41/3 h after 11 am i.e., at 3 : 20 pm.
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