Question

Two cells each of emf 10V and each 1 internal resistance are used to send a current through a wire of 2 resistance. The cells are arranged in parallel. Then the current through the circuit. 1 ) 2A 2) 4A 3) 3A 4) 5A​

Answer 1

Answer:

Hope the answer in the image is helpful!!!..

Answer 2

Suppose that a current i flows through the external resistance (8Ω) and it divides into two branches at the node B as i

1

and i

2

Using KCL, i

1

+i

2

=1

Using KVL

For loop ABYXA

(−i

1

)1+(i−i

1

)1=−10+8

for loop ABQPA

(−i

2

)1+(−i)8=−10

On solving we get

i=

17

18

A≈1.06A

i

1

=10−8i=(10−8.54)A=1.52A

i

2

=i−i

1

=−0.46A

The negative sign for i

2

means that its direction its opposite to the direction that we had assumed.

Give me some thanks

Mark Branlist please