Two cells having emf 4 V and 2 V and internal
resistances 1 S2, 1 12 are connected as shown in
figure. Current through 6 12 resistance is
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Answer:
As net resistance = 6 ohm
So by applying formulae
V = I.R
I = 1 Ohm
and the current in 6 ohm resistance is 1 / 3 amp.
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