Two cells of emf 1.5 V and 2 V and internal resistances 2 ohm and 1 ohm respectively
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What to find it seems to be incomplete question..
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Given :
E₁=1.5V E₂ =2.0V r₁=0.2Ω r₂=0.3Ω
Equivalent resistance of parallel combination : 1/r_eq=1/r₁+1/r₂
∴ 1/req = 1/0.2+1/0.3=(0.2+0.3)/(0.2ˣ0.3)
⇒r eq=0.12Ω
Equivalent Emf Eeq =[(E₁+E₂)/(r₁+r₂)]req
∴Eeq=[(1.5/0.2)+(2.0/0.3)]ˣ0.12
Eeq=[7.5+6.67]×0.12=1.7V
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