Question

two cells of EMF 1.5 volt and 2.0 volt having internal resistance is 0.2 ohm and 0.3 ohm respectively are connected in parallel calculate the EMF and internal resistance of the equivalent cell

Answer 1

✌️✌️✌️HIII. Neha✌️✌️

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Answer 2

Answer:

The emf and internal resistance of the equivalent cell are 1.7 V and 0.12 ohms.

Explanation:

Given that,

EMF $E_{1}=1.5 volt$

EMF$E_{2}=2.0 volt$

Internal resistance $r_{1} = 0.2$

Internal resistance $r_{2} = 0.3$

Effective emf of two cells connected in parallel is,

$E_{eff}=\dfrac{E_{1}r_{2}-E_{2}r_{1}}{r_{1}+r_{2}}$

$E_{eff}=\dfrac{1.5\times 0.3+2.0\times0.2}{0.2+0.3}$

$E_{eff}=1.7\ V$

Now, the effective resistance of equivalent cell is

$R_{eff}=\dfrac{r_{1}r_{2}}{r_{1}+r_{2}}$

$R_{eff}=\dfrac{0.2\times 0.3}{0.2+0.3}$

$R_{eff}=0.12\Omega$

Hence, The emf and internal resistance of the equivalent cell are 1.7 V and 0.12 ohms.