two cells of emf 1V and 2V and internal resistance 2 ohm and 1 ohm are connected first in series then in parallel. what should be the external resistance in the circuit so that the current through the resistance be same in the two cases? in which case more heat is generated in the cell?
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in series effective emf =2+1=3V
effective internal resistance =2+1=3ohm
total resistance =3+R ohm
where R=external resistance
current through the circuit=current through the external resistance =3/3+R ampere
in parallel effective emf =2V
effective resistance =2/3ohm
total resistance =2/3+R. ohm
current through the external resistance
=2/(2/3+R) Ampere
in two cases current is same
then solving two equation we get R=4ohm
as in series connection resistance is more so heat will generate more in series connection
hope this will help you
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effective internal resistance =2+1=3ohm
total resistance =3+R ohm
where R=external resistance
current through the circuit=current through the external resistance =3/3+R ampere
in parallel effective emf =2V
effective resistance =2/3ohm
total resistance =2/3+R. ohm
current through the external resistance
=2/(2/3+R) Ampere
in two cases current is same
then solving two equation we get R=4ohm
as in series connection resistance is more so heat will generate more in series connection
hope this will help you
you can follow me and mark me brainliest to answer thoroughly
dearmanmeet:
thnq soo much....thnq
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