two cells of emf 2v and 4v
Answers
Answered by
0
Answer:
Equivalent internal resistance of parallel connection r
eq
=
r
1
+r
2
r
1
r
2
∴ r
eq
=
1+2
1×2
=
3
2
Ω
Equivalent emf of cells in parallel connection E
eq
=[
r
1
E
1
+
r
2
E
2
]r
eq
∴ E
eq
=[
1
2
+
2
4
]×
3
2
=
3
8
V
Potential difference across 10Ω resistor, E=
R+r
eq
R
E
eq
∴ E=
10+
3
2
10
×
3
8
=2.5V
Answered by
1
Answer:
Two cells of emf 2v and 4v and internal resistance 1 ohm and 2 ohm respectively are connected in parallel so as to send current in the same direction through an external resistance of 10 ohm. Find the potential difference across 10 ohm resistor. akashshirur6 is waiting for your help.
Explanation:
@darksoul
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