Question

Two cells of EMF 3 volt and 4 volt and internal resistance 1 ohm and 2 ohm respectively are connected in parallel so as to send current in the same direction through an external resistance of 5 ohm 1.Draw circuit diagram
2. Using kirchoffs law calculate the current through each branch of the circuit and potential difference across the 5 ohm resistance.




plzzzz help me tommorow is my test..​

Answer 1

Answer:

25

Explanation:

I=V/R then , in parallel connected to the cell so that if two cell of emf connected in parallel into same direction through an internal into external resistance in current flow of two cell

3/1+4/2= 5

then I=5

I=V/R

5x5 =25. volt