Question

two cells of emf 4v and 6v and internal resistance 1 ohm and 2ohm respectively are connected in parallel so as to send the current in the direction through an external resistance of 20 ohm find the potential difference across 20 ohm resistor

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Answer 1

Answer:

1002

I= I₁+I₂

2012

B

1002

2V

4

Let the Potential at point (junction) B = 0 Let the Potentiat at point (juvetion) A = V

I, I₂ = = 2- V 10 1.5-V 20

I

=

V

I = I₁+I₂

Y = 2-1 +115-V 20

2v = 4-2v +1.5-V

5V = 5.5

V = 1.$

I₁ I₂ = 2-0 = 2-4-4 = 0,9 = 90md 10 1.5-1.1 = 0.4 = 20mA 20 20 1.5-V 20

工=

I₁+I₂ = 90+20= 110m A

Answer 2

Answer:

your answer is in the image please mark as brainlist answer