Two cells of emf and having internal resistance and
respectively are connected in parallel.calculate the emf and
internal resistance of the equivalent
ld having internal resistances and
connected in parallel. Calculate the emf and
the equivalentcell.
Answers
The equivalent emf of the two cells is 1.7 V and the equivalent resistance is 0.12 Ω
Explanation:
Complete statement:
Two cells of emf 1.5 v and 2.0 v having internal resistance 0.2 ohm and 0.3 ohm and respectively are connected in parallel. Calculate the emf and internal resistance of the equivalent.?
Solution:
Electro Motive Force:
E1 = 1.5 V E2 = 3 V
Internal resistance r = 0.2 Ω and 0.3 Ω
Effective emf of two cells connected in parallel is.
E (eff) = E1r2 + E2r1 / r1 + r2
This implies that:
E (eff) = 1.5 x 0.3 + 2 x 0.2 / 0.5 = 1.7 V
R (eff) = r1r2 / r1 + r2
R (eff) = 0.2 x 0.3 / 0.5 = 0.12 Ω
Thus the equivalent emf of the two cells is 1.7 V and the equivalent resistance is 0.12 Ω
Also learn more
A battery emf 10 V and internal resistance 5 ohm is connected to a resistor.The current in the circuit is 0.5 A. What is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
https://brainly.in/question/10410771