Two cells of equal emf 50v and of internal resistances r1=5 ohm and r2=3 ohm are connected in series. This arrangement is connected to an external resistance 'x'
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Resistance in series is equal to r1+r2+r3
R=5+3=8
R=8
V=IR
R=V/I
R=50/8
R=6.25ohm. Ans.
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