Two cells of same emf e but internal resistance r1 and r2 are connected in series to an external resistor r.What should be the value of r so that the potential differences across the terminalsof first cell become zero
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In this solution first we apply Ohm's law to find current in the circuit .
Effective emf of two cells = E + E = 2E
Effective resistance = R + r1 + r2
So the electric current is given by
I = E + E / R + r1 + r2
The potential difference across the terminals of the cell and putting it equal to zero.
R=ri-r2
Explanation:
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