Two cells of the same emf E have different
internal resistances r₁ and r₂. They are connected in series
with an external resistance R and the potential difference
across the first cell is found to be zero. Therefore, the
external resistance R must be
(a) r₁ – r₂ (b) r + r₂
(c) 2r₁ – r₂ (d) r₁ – 2r₂
Answers
Answered by
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(c) 2r₁ – r₂
Answered by
4
Answer:
c) 2r₁ – r₂
Explanation:
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