Two charge 5uC and -4uC are kept 5.0
m apart at points A and B respectively,
How much work will have to be done to
move the charge at A through a distance
of 5.0 m further away from point B along the line BA
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Answered by
12
Answer:
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Explanation:
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Answered by
11
Answer:
Lets say charge 'B'(Q = -4μC) is fixed as and 'A'(q = 5μC) is moved. We think of this situation as moving charge A in the B's electric field.
Work done in moving a charge in electric field, W = qΔV
q = 5μC
W = q(Vf - Vi)
Vf = KQ/Rf = (9*10⁹ x -4*10⁻⁶)/10m = -3600V
Vi = KQ/Ri = (9*10⁹ x -4*10⁻⁶)/5m = -7200V
ΔV = Vf - Vi = -3600V- (-7200V) = 3600V
W = qΔV = 5μC x 3600V = 18mJ = 1.8x10⁻⁴ J
Work in moving A in the electric field of B,
W = 1.8x10⁻⁴ J
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