Question

Two charge of 1C each are placed 1M apart in free space. The force between them will be

Answer 1

Answer:

9*$10^{9}$ N

Explanation:

From the Coulomb's Force Formula,

$F = (kq_{1} q_{2} )/r^{2}$

As we are given that the charges are both 1C, and the distance (r) is 1m,

Replacing values,

F = 9*$10^{9}$1*1/1     (Value of k is a constant)

F = 9*$10^{9}$ N

Answer 2

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Explanation:

use formula ,F= kq1q2÷ r^2

answer will come 9×10^9 N