two charge of 64 micro coloumb and 36 micro columb are placed in 1 m apart with dielectric constant 2.5 find force between them?
Answers
Explanation:
two charge of 64 micro coloumb and 36 micro columb are placed in 1 m apart with dielectric constant 2.5 find force between them?
Answer:
In vacuum force of repulsion =
4πε
0
1
(1)
2
q
1
q
2
given the force of repulsion is same in oil so let the distance in oil be X.
⇒
4πε
0
1
(1)
2
q
1
q
2
=
4πKε
0
1
X
2
q
1
q
2
⇒
1
K
=
X
2
1
⇒4=
X
2
1
⇒2=
X
1
⇒X=0.5m
In vacuum force of repulsion =
4πε
0
1
(1)
2
q
1
q
2
given the force of repulsion is same in oil so let the distance in oil be X.
⇒
4πε
0
1
(1)
2
q
1
q
2
=
4πKε
0
1
X
2
q
1
q
2
⇒
1
K
=
X
2
1
⇒4=
X
2
1
⇒2=
X
1
⇒X=0.5m
Explanation: