Question

two charge of one coloumb each are placed 1 cm apart in a medium of dielectric constant 1.5 calculate the force between the two charges?​

Answer 1

Answer:

1.5×{(1×1)÷1^2} = 1.5

Explanation:

from Coloumb's equation we get that

F =K×{(q1×q2)÷r^2}