Physics, asked by lahariyadav4773, 1 year ago

Two charge of value 2mewC and_50mewC are placed 80cm apart calculate the distance of the point from the smaller charge where the intensity will be zero

Answers

Answered by kamla19nama
1
length AB=200m=2R

time taken to complete one round=40 sec

let the starting point be A

in 140 sec or 2 min 20 sec number of rounds completed=14040=3.514040=3.5

distance traveled=3.5 * (2*ππ*R)=3.5*2*ππ*100 m=2200 m (approx)

displacement refers to change in position from the starting point.the final point is B

as after 3.5 revolutions(starting from A) the athlete will be at B.

displacement=200m
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