Two charge particles with charge ratio 1:2 and mass ratio 1:4 have been accelerated through same potential difference. Find the ratio of DE BROGLIE wavelengths.
The particles are initially at rest.
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Answer:
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Explanation:
λ = h/√(2mqV)
λ α 1/√(mq)
λ₁ α 1/√(mq)
λ₂ α 1/√(4m*2q)
α 1/√(8mq)
λ₁/λ₂ = √8 / 1
= 2√2 / 1
λ₁ : λ₂ = 2√2 : 1
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