Two charged body of mass m and 2m separated by distance d at what point they collid
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solution:
He conservation law of momentum gives you
v2v1=−m1m2v2v1=−m1m2
Substitute this into v1- v2 giving v1(m1+m2)/m2.
We can also apply momentum conservation again to the kinetic energy ratio
k1k2=m2m1k1k2=m2m1.
That's nice, and it eliminates an energy :
k1+k2 = k1(m1+m2)/m2
now, we set that to Gm1m2/r
But the pesky k1 still needs to be removed, so expand it giving
v1^2 = 2Gm2^2/(m1+m2)r
The easy way to finish off is square the relative velocity
Vrel^2 = v1^2 * ((m1+m2)/m2)^2 and just plug in v1^2
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