Question

two charged liquid drop each having capacitancr 10*10^-6F ate combined to form a bigger drop calculate capacitance of bigger drop

Answer 1

Hey Buddy,

◆ Answer -

C = 12.6 μF

● Explanation -

Let r & R be the radii of small drop & large drop respectively.

As two small drops are combined to formed one large drop,

v + v = V

2 × 4/3 πr^3 = 4/3 πR^3

2 r^3 = R^3

R = ∛2 r

R = 1.26 r

Capacitance of the drop is directly proportional to radius.

C/c = R/r

C = 1.26r/r × 10×10^-6

C = 1.26×10^-5 F

C = 12.6 μF

Therefore, capacitance of the big drop will be 12.6 μF.

Best luck for exams..