Question

two charged particles apply an electron force of 5.2×10 -³N on each other. Distance between them gets twice as much as before what will be coulumbs force?​

Answer 1

$Given:-</p><p>\\F_1=5.2\times10^{-3}</p><p>\\F_2=?</p><p>\\r_2=2r_1</p><p></p><p>\\frac{F_2}{F_1}=\frac{\frac{kq_1q_2}{r_2^2}}{\frac{kq_1q_2}{r_1^2}}</p><p>\\frac{F_2}{F_1}=\frac{r_1^2}{(2r_2)^2}=\frac{1}{4}</p><p> \\ F1=45.2× {10}^{ - 3}</p><p> \\ F2=1.3× {10}^{ - 3} N</p><p>$