Two charged particles are 8.45cm apart. They are moved and the force on each of them is found to have tripled. How far are they now?
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We can find the distance between two charged particles next way:
3F/F=(q1q2/x^2)/(q1q2/8.45^2)
3=8.45^2/x^2
x=8.45/sqrt(3)
Answer: 4.88 cm
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