Two charged particles are placed at a distance of 1 cm apart. What is the minimum possible magnitude of the electric force acting on each charge??????
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93
F = KQq/r²
hence , magnitude of force depends upon products of magnitude of charges
and distance between them .
but here distance between charge particle is fixed so,
only depends upon product of magnitude of charge .
we know smallest charge = 1.6 × 10-19C
of electrons exist in nature .
so, if we choose both charge particle " electrons " then force will be minimum.
now,
F = Ke²/r²
= 9× 10^9 × (1.6 × 10^-19)²/(1/100)²
= 9 × 2.56 × 10^-29+4 N
= 23.04 × 10^-25 N
= 2.304 × 10^-24 N
hence , magnitude of force depends upon products of magnitude of charges
and distance between them .
but here distance between charge particle is fixed so,
only depends upon product of magnitude of charge .
we know smallest charge = 1.6 × 10-19C
of electrons exist in nature .
so, if we choose both charge particle " electrons " then force will be minimum.
now,
F = Ke²/r²
= 9× 10^9 × (1.6 × 10^-19)²/(1/100)²
= 9 × 2.56 × 10^-29+4 N
= 23.04 × 10^-25 N
= 2.304 × 10^-24 N
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