Two charged spheres A and B have identical size and charge Q separated by a distance R. A third sphere of the same but uncharged is placed in contact with the first the brought in contact with the second and finally removed from both. what is the new force of repulsion between A and B?
Answers
Answered by
4
Answer:
When sphere A is touched with an uncharged sphere C, q/2 amount of charge from A will transfer to sphere C. Hence, charge on each of the spheres, A and C, is q/2.
When sphere C with charge q/2 is brought in contact with sphere B with charge q, total charges on the system will divide into two equal halves given as,1/2 (q + q/2) = 3q/4
acc. to coulomb's law
f = k q1×q2 / r^2
=k 1q/2 × 3q/4 ÷ r^2 ------------' equation 1
| --------------------------|
| |
| k = 9 ×10^9 |
| r = 1/2 |
| q = 1.6 ×10^-19 |
|________________|
put all the value in equation 1
Similar questions