Question

two charged spheres with charges of 2 into 10 power minus 7 coulomb and 3 into 10 ki power minus 7 coulomb are placed at 30 cm apart in the air calculate the force between these two charges​

Answer 1

Answer:

6×10^-3 N

Explanation:

let,

q1= 2×10^-7 C

q2= 3×10^-7 C

r= 30cm= 0.3m

K= 9×10^9Nm^2C^-2

By Coulomb's Law,

F= Kq1q2/r^2

= 9×10^9×2×10^-7×3×10^-7/0.3×0.3

=54×10^-5/0.3×0.3

= 6×10^-3 N