two charges 16 microcoulomb and 9 microcoulomb are 6 CM apart calculate the point on the line joining them where the net electric field is zero
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Answer:24/7cm
Explanation: let a distance x from
Bigger charge where electric field is zero due to 16 microcoulomb and 9 microcoulomb
means electric field due to 16 microcoulomb and 9 microcoulomb at that point is equalmeans 16 into 10 raise to power minus 6 / x square is equals to 9 into 10 raise to power minus 6 upon 6 - X ka whole square
=24 - 4 x is equals to 3 X and X is equals to 24 by 7
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