Question

two charges 1C and -1C are kept separated by a distance of 1m in water having k=1.5 find the magnitude of force between them​

Answer 1

Answer:

1.5

Explanation:

F=k q1q2/r^2

F=1.5 1*1/1^2

F=1.5N

Answer 2

Answer:

Two charges 1C and -1C are kept separated by a distance of 1m in water having k=1.5, the magnitude of the force between them​ is $/F/=6*10^{9} N$

Explanation:

• The interaction between two charges at rest is called electrostatic force

• The coulomb's law gives the magnitude of the force as

                     $F=\frac{q_{1} q_{2} }{4\pi \varepsilon _0 K r^{2} }$

       where $q_{1} ,q_{2}$- the charges

       $\frac{1}{4\pi \varepsilon _0}=9*10^{9}$

      $K$- dielectric constant of the medium

      $r$- separation between the charges

From the question, we have

the charges are $q_{1} =1C ,q_{2} =-1C$

the distance between the charges $r=1m$

the dielectric constant of the medium $K=1.5$

substitute the values, we get

$/F/=\frac{9*10^{9}*1*1 }{1.5*1^{2} }$

⇒ $/F/=6*10^{9} N$