Question

two charges 2 into 10 to the power minus 6 coulomb and 1 into 10 to the power minus 6 coulomb are placed at a separation of 10 cm where should the third charge be placed such that it experiences no net force due to this charges​

Answer 1

Answer:

Explanation:

If both are positive charges then the third charge should be placed on the line joining the two charges.

it should be in between the two charges

F1=F2

2*q/ r2=1*q/(10-r)2

r2=2(10-r)2

r2= 200 + 2 r2 - 40r

r2 - 40r + 200 = 0

r = [40 ± √(1600-800)]/2

= [40 - √(1600-800)]/2 since the point should be in between

= 20 - 10√2

= 5.86 cm

third charge should be placed at 5.86 cm from 2*10-6 C charge.