Question

two charges 2microC and 8 microC are placed atbx=0 and x= 3 on x axis respectively the position between the two charges where net electric field is 0​

Answer 1

Answer:

E

1

=

(l+d)

2

K(8q)

E

2

=

d

2

K(−2q)

E

net

=E

1

+E

2

=0

=

(l+d)

2

K(8q)

−

d

2

K(2q)

=0

⇒

(l+d)

2

4

=

d

2

1

⇒2d=d+l

Position of point is x=d+l=2l