Question

Two charges 3×10_19c and _3×10_19c are placed at 2.4A apart from an electric dipole It is placed in an uniform electric field of intencity 4×105 volt/m the electric dipole moment is

Answer 1

Given : Two charges +3.2 ×10^-19c and -3.2 ×10^-19c are placed at 2.4A apart from an electric dipole It is placed in an uniform electric field of intensity 4 × 10^5 volt/m.

To find : dipole is a system of two unlike charges of equal magnitudes are seperated very small distance.

dipole moment is the product of magnitude of charge and seperation between charges.

i.e., P = q × d

here , q = 3.2 × 10^-19 , d = 2.4 A = 2.4 × 10^-10 m

so, dipole moment, P = 3.2 × 10^-19 C × 2.4 × 10^-10 m

= 7.68 × 10^-29 Cm

Therefore dipole moment would be 7.68 × 10^-29 Cm.

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