Question

Two charges +3.2 x 10-19C and —3.2 x 10-°C
kept 2.4 Å apart forms a dipole. If it is kept in uniform electric field of
intensity
4 x 10 volt/m then what will be its electrical energy in equilibrium​

Answer 1

Answer:

Given here

q = 3.2×10^-19

distance between dipole, d= 2.4×10^-10m

and E= 4×10^5

now p = qd

and

we know U=pE

all value are given here multiply them then u will got it ans.

Mukesh Saharan answered Jul 16, 2019

Yrr ab reply nhi deti ho

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