Question

Two charges + 3 microcoulomb and + 4 microcoulomb are placed in free space 12 metre apart. What is the potential at the the midpoint on the the line joining these two charges?

Answer 1

Answer:

ANSWER

Given : Q

1

=3×10

−6

C Q

2

=4×10

−6

C r=2cm=0.02 m

Coulomb force between them F=

r

2

KQ

1

Q

2

where K=

4πϵ

o

1

=9×10

9

Nm

2

C

−2

∴ F=

(0.02)

2

9×10

9

×(3×10

−6

)×(4×10

−6

)

=270 N