Two charges 4μC and 1μC are placed at a distance of 10cm. Where should a third charge be placed between them so that it does not experience any force.
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Explanation:
Correct option is
B
5.858 cm from 2μC
Let the charge is placed at distance x from 2μc
Now the net force acting on charge q should be zero.
⇒
(10−x)
2
k(1×10
−6
)q
=
x
2
(2×10
−6
)q
⇒
10−x
1
=
x
2
⇒x=10
2
−x
2
⇒x(1+
2
)=10
2
⇒x=
1+
2
10
2
⇒x=
2.414
14.14
⇒x=5.857cm
solution
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