Question

Two charges 4μC and 1μC are placed at a distance of 10cm. Where should a third charge be placed between them so that it does not experience any force.

Answer 1

Explanation:

Correct option is

B

5.858 cm from 2μC

Let the charge is placed at distance x from 2μc

Now the net force acting on charge q should be zero.

⇒

(10−x)

2

k(1×10

−6

)q

=

x

2

(2×10

−6

)q

⇒

10−x

1

=

x

2

⇒x=10

2

−x

2

⇒x(1+

2

)=10

2

⇒x=

1+

2

10

2

⇒x=

2.414

14.14

⇒x=5.857cm

solution