Question

Two charges 4 microcolumb and 16microcolumb are separated by a distance of 0.1m the null point along the line joining the charges and between them is at a distance x from the weaker charge. The value of x is

Answer 1

Answer:

Explanation:

for null point force due to charge 1(16 micro coloumb)is equal to force due to charge 2

force due to charge 1 is (k×q1)÷x²

similarly force du to charge 2(4 micro coloumb) is (k×q2)÷(0.1-x)²

F1 =F2

on substituting values

we get 1÷(0.1 - x)=4÷x

x=0.4-4x

5x=0.4

x=0.4/5

x=0.008

Answer 2

Answer:

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