Physics, asked by DevduttNair250, 1 year ago

Two charges 4q and q are placed at a distance of 30 cmapart

Answers

Answered by PSN03

0

F=kq1q2/r^2

r=0.3m

q1=4q

q2=q

F=9*10^9*4q^2/0.09

=4q^2*10^11 N

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