Physics, asked by kjesnajose, 1 year ago

Two charges-4uc &8uc are 27cm apart.The distance from the-4uc charge on the line joining the charges where electric potential would be 0 is
(A) 10 cm
(B) 9cm
(C)20cm
(D)21cm

Answers

Answered by avelinteresa

0

Answer:

9 cm

Explanation:

Va+Vb=0

kq/x =-kq/27-x

-4//x=-8/27-x

108-4x=8x

x=9

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