Question

Two charges -5 ° C and +10 uc are placed 20 cm apart . The potential energy of the system is​

Answer 1

Explanation:

Let the two charges placed at two points of line AB as A and B whose distance is 20 cm and O is the mid point of the line AB

Distance between the two charges , AB=20 cm

∴AO=OB

Net elctric at O=E

Electric field at point O caused by +5\mu C charge,

E

1

=

4πε

0

(AO)

2

5×10

−6

=

4πε

0

(10×10

−2

)

2

5×10

−6

N/C toward +5μC

where,

ε

0

=Permittivity of free space

4πε

1

=9×10

9

Nm

2

C

−2

Magnitude of electric field at point O cause by +10\mu C charge,

E

1

=

4πε

0

(AO)

2

10×10

−6

=

4πε

0

(10×10

−2

)

2

10×10

−6

N/C towards +10μC

∴E=E

1

+E

2

=

(10×10

−2

)

2

9×10

9

×15×10

−6

=13.5×10

6

N/C towards +5μC